单项选择题
What can cause a thread to become non-runnable？（）
A. Exiting from a synchronized block.
B. Calling the wait method on an object.
C. Calling the notify method on an object.
D. Calling the notifyAll method on an object.
相关考题
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单项选择题
public class A extends Thread { A（） { setDaemon（true）； } public void run（） { （new B（））.start（）； try { Thread.sleep（60000）； } catch （InterruptedException x） {} System.out.println（“A done”）； } class B extends Thread { public void run（） { try { Thread.sleep（60000）； } catch （InterruptedException x） {} System.out.println（“B done”）； } } public static void main（String[] args） { （new A（））.start（）； } } What is the result？（）
A. A done
B. B done
C. A done B done
D. B done A done
E. There is no exception that the application will print anything.
F. The application outputs “A done” and “B done”， in no guaranteed order. -
单项选择题
public class X implements Runnable { private int x； private int y； public static void main（String [] args） { X that = new X（）； （new Thread（ that ））.start（）； （new Thread（ that ））.start（）； } public void run（） { for （；；） { synchronized （this） { x++； y++； } System.out.println（Thread.currentThread（）.getName（） + “x = “ + x + “， y = “ + y）； } } } What is the result？（）
A. Compilation fails.
B. The program prints pairs of values for x and y that might not always be the same on the same line （for example， “x = 2， y = 1”）.
C. The program prints pairs of values for x and y that are always the same on the same line （for example， “x = 1， y = 1”）. In addition， each value appears only once （for example， “x = 1， y = 1” followed by “x = 2， y = 2”）. The thread name at the start of the line shows that both threads are executing concurrently.
D. The program prints pairs of values for x and y that are always the same on the same line （for example， “x = 1， y = 1”）. In addition， each value appears only once （for example， “x = 1， y = 1” followed by “x = 2， y = 2”）. The thread name at the start of the line shows that only a single thread is actually executing. -
单项选择题
class MyThread extends Thread { public void run（） { System.out.println（“AAA”）； } public void run（Runnable r） { System.out.println（“BBB”）； } public static void main（String[] args） { new Thread（new MyThread（））.start（）； } } What is the result？（）
A. AAA
B. BBB
C. Compilation fails.
D. The code runs with no output.
